a programming definition for Stupidity
- 4 years ago
the next question is, if you can define stupidity then the inverse of stupidity is intelligence. that makes sense but i had to think about it for a while to detail it better.
when you start a movement then are stopped that is a semi movement. this is stupidity.
to correct this you not only complete the semi movement but you also repeat the movement until it ends its loop condition.
the previous code is here:
the first value is OR, and AND fits into OR
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 0
8 bits = (AL, or BL, or CL, or DL) = 1
the second value is AND, and AND fits into AND by including good.
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 1
8 bits = (AL, or BL, or CL, or DL) = 1
so the first AND has no good so it has one value this is why OR can hold AND.
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 0
8 bits = (AL, or BL, or CL, or DL) = 1
THEN AND adds in another value to fit in the AND memory size and type so AND is both good (AH, or BH, or CH, or DH), and bad (AL, or BL, or CL, or DL).
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 1
8 bits = (AL, or BL, or CL, or DL) = 1
The third value is OR, and AND fits into OR by zeroing out the larger AND to the size of OR.
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 0
8 bits = (AL, or BL, or CL, or DL) = 1
then OR is fit back into AND as AND has a much larger size available which removes OR.
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 1
8 bits = (AL, or BL, or CL, or DL) = 1// this is the semi movement.
the new code is below
is OR, and AND fits into OR by zeroing out the larger AND to the size of OR, looping until the condition is completed..
32 bits = (EAX, or EBX, or ECX, or EDX) = 0
16 bits = (AX, or BX, or CX, or DX) = 0
8 bits = (AH, or BH, or CH, or DH) = 0
8 bits = (AL, or BL, or CL, or DL) = 1